Answer to Question #27244 in Mechanics | Relativity for Vishal Prasad
with the same speed. The ball remains in contact with the surfacefor 0.01
sec.Then what will be the average force exerted by the surface onthe ball?
Newton's second laws of motion:
F = dp/dt;
F - force;
p - momentum;
t - time;
For average force:
F = Δp/Δt;
Δp = m*v - (-m*v) = 2m*v;
m - mass of the body;
v - velocity;
Δt = 0.01 sec;
F = 2mv/Δt = (2*0.01kg*5m/s)/(0.01sec) = 10 N;
Answer: the average force equals 10 N.
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