Answer to Question #26770 in Mechanics | Relativity for apronia
To find how much thepuck has moved in this 2 seconds we have to take t=2 in the given equation
x = 4*2^3+2*2^2+2 =32+8+2 = 42 m
Hence, he moved 42 m.
To find velocity wefind derivative of the given function x(t)
x' = 12t^2+4t+1
Velocity of the puckat two seconds we find taking t=2 in this new function
v= 12*2^2+4*2+1 =48+8+1= 57m/s
To find accelerationwe find second derivative of x(t)
x'' = 24t+4
Acceleration of thepuck at 2 s can be found by putting t=2 in it.
a = 24*2+4=48+4= 52m/s^2
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