Question #26243

A bullet, when fire at a fixed target, has its speed decreased to 50% after penetrating 15cm in to it. What additional thickness it will penetrate before coming to rest?

Expert's answer

A bullet, when fire at a fixed target, has its speed decreased to 50%

after penetrating 15cm in to it. What additional thickness it will

penetrate before coming to rest?

Let the velocity of a bullet was V before hitting target. Then the kinetic energy of a bullet was

K1 = mV²/2.

As after penetrating 15cm into a target bullet's speed decreased to 50%, its kinetic energy became

K2 = m(V/2)²/2 = mV²/8.

Assuming that the bullet's energy decreases linearly while penetrating a target. Then the amount of energy needed to penetrate one cm of a target is

E = (K1 - K2)/15 = (mV²/2 - mV²/8)/15 = mV²/40.

Therefore the bullet will penetrate

D = K2/E = (mV²/8) / (mV²/40) = 5 [cm]

more before coming to rest.

after penetrating 15cm in to it. What additional thickness it will

penetrate before coming to rest?

Let the velocity of a bullet was V before hitting target. Then the kinetic energy of a bullet was

K1 = mV²/2.

As after penetrating 15cm into a target bullet's speed decreased to 50%, its kinetic energy became

K2 = m(V/2)²/2 = mV²/8.

Assuming that the bullet's energy decreases linearly while penetrating a target. Then the amount of energy needed to penetrate one cm of a target is

E = (K1 - K2)/15 = (mV²/2 - mV²/8)/15 = mV²/40.

Therefore the bullet will penetrate

D = K2/E = (mV²/8) / (mV²/40) = 5 [cm]

more before coming to rest.

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