Answer to Question #25566 in Mechanics | Relativity for doug
E=sigma/epsilon = (F/S)/(delta L/L)
where F is is the force exerted on an object, S=pi*(d/2)^2 is cross-section area of wire delta L is the amount by which the length of the object changes. So,
E = (mg/S)/(delta L/L) = 6.1*9.8/(pi*(0.0013/2)^2)/(0.0014/2.1) = 67.5 * 10^9 Pa
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