Question #25540

the position of a train along it tracks as a function of time is plotted as a graph. at t1=6.0secs x1=48.5m at t2=8.50secs x2=73.5m. find the average velocity of this body in k/h.

Expert's answer

V - an average speed

S - a total distance

t - a total time

V = S/t

S = x2 - x1

t = t2 - t1.

Therefore:

V = (x2 - x1)/(t2 - t1) = (73.5m-48.5m)/(8.5sec-6sec) = 25m/2.5sec = 10m/sec

In km/h:

V = 10m/sec * 3600sec/1h * 1km/1000m = 10*3.6 km/h = 36 km/h

S - a total distance

t - a total time

V = S/t

S = x2 - x1

t = t2 - t1.

Therefore:

V = (x2 - x1)/(t2 - t1) = (73.5m-48.5m)/(8.5sec-6sec) = 25m/2.5sec = 10m/sec

In km/h:

V = 10m/sec * 3600sec/1h * 1km/1000m = 10*3.6 km/h = 36 km/h

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