A simple pendulum 99.5 cm long is observed to have a period of 2.05 s at a certain place. Determine the acceleration of gravity at the place.
For simple pendulum: T = 2*pi*Sqrt [L/g], T - pendulum period pi = 3.14 L - pendulum length g - acceleration of gravity Therefore: g = L * (2*pi/T)^2 = 0.995m* ( 2*3.14/2.05 s)^2 = 9.35 m/s^2 Answer: g = 9.35 m/s^2
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