Question #25127

How much work was required to bring the 1000-kg roller coaster from point P to rest at point Q at the top of the 50-m peak?

Expert's answer

The work is equal to the change of potential energy V ofthe coaster.

The value of V at the height h is equal to V(h) = m*g*h,

where g=9.8 m/s^2. Thus,

A = V(h) - V(0)

= m * g * h - 0 =

= m * g * h =

= 1000 * 9.8 * 50

= 490000 J.

The value of V at the height h is equal to V(h) = m*g*h,

where g=9.8 m/s^2. Thus,

A = V(h) - V(0)

= m * g * h - 0 =

= m * g * h =

= 1000 * 9.8 * 50

= 490000 J.

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