Two identical billiard balls undergoes an oblique collision initially one of the ball is stationary if the initially stationary ball after collision moves in a direction which makes an angle of 37 with direction of intial motion of the moving ball then the angle through which initially moving ball will be deflected is
1
Expert's answer
2013-02-20T09:20:02-0500
The law of conservation of energy: T0 = T1 + T2 T - kinetic energy, T = mv^2/2 Therefore (m1 = m2 ): v0^2 = v1^2 + v2^2 The law of conservation of momentum: p0 = p1 + p2 p= m*v p0^2 = p1^2 + p2^2 + 2p1*p2*cos(alpha) alpha - angle between p1 and p2 Therefore: v0^2 = v1^2 + v2^2 + 2*v1*v2*cos(alpha) From laws of conservations: cos(alpha) = 0 => alpha = 90 the angle through which initially moving ball will be deflected is: 90 - 37 = 53 Answer: 53
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