Question #24636

Two identical billiard balls undergoes an oblique collision initially one of the ball is stationary if the initially stationary ball after collision moves in a direction which makes an angle of 37 with direction of intial motion of the moving ball then the angle through which initially moving ball will be deflected is

Expert's answer

The law of conservation of energy:

T0 = T1 + T2

T - kinetic energy, T = mv^2/2

Therefore (m1 = m2 ):

v0^2 = v1^2 + v2^2

The law of conservation of momentum:

p0 = p1 + p2

p= m*v

p0^2 = p1^2 + p2^2 + 2p1*p2*cos(alpha)

alpha - angle between p1 and p2

Therefore:

v0^2 = v1^2 + v2^2 + 2*v1*v2*cos(alpha)

From laws of conservations:

cos(alpha) = 0 => alpha = 90

the angle through which initially moving ball will be deflected is:

90 - 37 = 53

Answer: 53

T0 = T1 + T2

T - kinetic energy, T = mv^2/2

Therefore (m1 = m2 ):

v0^2 = v1^2 + v2^2

The law of conservation of momentum:

p0 = p1 + p2

p= m*v

p0^2 = p1^2 + p2^2 + 2p1*p2*cos(alpha)

alpha - angle between p1 and p2

Therefore:

v0^2 = v1^2 + v2^2 + 2*v1*v2*cos(alpha)

From laws of conservations:

cos(alpha) = 0 => alpha = 90

the angle through which initially moving ball will be deflected is:

90 - 37 = 53

Answer: 53

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