# Answer to Question #23645 in Mechanics | Relativity for Lea

Question #23645

A car moving along a straight level road has an initial velocity of 16ms^-1. It's deceleration is 2ms^-2. How long does it take for the car to stop?

Expert's answer

a = dv/dt

a - acceleration ( -a - deceleration )

v - velocity

t - time

Therefore:

v = a*t + v0

v0 - initial velocity

In our case:

v = 0 = 16 - 2*t ( car stops)

t = 16/2 = 8 seconds

Answer: 8 seconds.

a - acceleration ( -a - deceleration )

v - velocity

t - time

Therefore:

v = a*t + v0

v0 - initial velocity

In our case:

v = 0 = 16 - 2*t ( car stops)

t = 16/2 = 8 seconds

Answer: 8 seconds.

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