Question #23497

A train is traveling down a straight track at 26 m/s when the engineer applies the brakes, resulting in an acceleration of −1.0 m/s2 as long as the train is in motion. How far does the train move during a 52-s time interval starting at the instant the brakes are applied?

Expert's answer

The train will stop at time t:

v - a*t = 0

a - an acceleration

v - initial speed

t = v/a = 26/1 = 26 seconds

During this time it will cover the distance d:

d = v*t - a*t^2/2 = 26*26 - 1*26*26/2 = 26*13 = 338 m

For the next 26 seconds it will stand still.

Answer: 338 m.

v - a*t = 0

a - an acceleration

v - initial speed

t = v/a = 26/1 = 26 seconds

During this time it will cover the distance d:

d = v*t - a*t^2/2 = 26*26 - 1*26*26/2 = 26*13 = 338 m

For the next 26 seconds it will stand still.

Answer: 338 m.

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