Answer to Question #22833 in Mechanics | Relativity for matt
of 12 m/s to the right. A stationary receiver
catches the ball and brings it to rest in 0.023
What is the force exerted on the receiver?
Answer in units of N
F=0.43*a -& exerted force
a=v/t=12*0.023 - we find the acceleration, that stopped the ball while force was exerted
So F=0.43*12/0.023=224 N - we put in numbers to find the answer
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!