# Answer to Question #22566 in Mechanics | Relativity for glezel monique polon

Question #22566

1. Determine the absolute pressure at the bottom of a lake that is 30 meters deep.

Expert's answer

The water pressure at the bottom of a lake that is 30 meters deep according to the Pascal's law is

P(water) = pgh = 1000[kg/m³]·9.8[m/s²]·30[m] = 294000[N/s²] = 294000 [Pa].

The usual atmospherical pressure is

P(atm) = 10^5[Pa].

Therefore, the absolute pressure at the bottom of a lake is

P(total) = P(water) + P(atm) = 294000[Pa] + 100000[Pa] = 394000[Pa].

P(water) = pgh = 1000[kg/m³]·9.8[m/s²]·30[m] = 294000[N/s²] = 294000 [Pa].

The usual atmospherical pressure is

P(atm) = 10^5[Pa].

Therefore, the absolute pressure at the bottom of a lake is

P(total) = P(water) + P(atm) = 294000[Pa] + 100000[Pa] = 394000[Pa].

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