Answer to Question #22263 in Mechanics | Relativity for Shane
t = 400 / 2 = 200 s
The maximum force that could be applied to a cable is:
Fmax = P * t / d = 500000 * 200 / 400 = 250000 N
The number of boxes can the elevator accommodate atone time is n = (Fmax - Fempty) / (m0 * g), where m0 is the mass of single box.
n = (250000 - 1000) / (60 * 10) = 249000 / 600 = 2490 / 6 = 415 boxes.
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