# Answer to Question #22108 in Mechanics | Relativity for mohamed

Question #22108

A block weighing 98.0 N falls 64.0 m.

(a) What is the potential energy of the block at 64.0 m?

(b) What speed does the block have as it strikes the ground?

(a) What is the potential energy of the block at 64.0 m?

(b) What speed does the block have as it strikes the ground?

Expert's answer

(a) Potential energy isE=F*h = 98.0 N *64.0 m = 6272 J

(b)velocity we can find from energy conservation

E=mv*2/2= 6272J

wherem is mass, m=F/g = 98/9.8 = 10kg

v= sqrt(2E/m) = sqrt(2*6272J/10) =

(b)velocity we can find from energy conservation

E=mv*2/2= 6272J

wherem is mass, m=F/g = 98/9.8 = 10kg

v= sqrt(2E/m) = sqrt(2*6272J/10) =

**35,4 m/s**Need a fast expert's response?

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