# Answer to Question #22107 in Mechanics | Relativity for mohamed

Question #22107

A 15.0 kg object is moving with a velocity of +7.50 m/s. A force of -10.0 N acts on the object and its velocity becomes 3.20 m/s. What is the displacement of the object while the force acts?

Expert's answer

The work done by a constant force of magnitude

A = F*d

The law of conservationof energy:

T1 + A = T2

T - kinetic energy

T = mv^2/2

A = T2 - T1 = m/2 (v2^2- v1^2)

v1= 7.5 m/s, v2 = 3.2 m/s

d= A/F = m/(2F) (v2^2 - v1^2) =15/(2*10) * (7.5^2 - 3.2^2) = 34.5 m

*F*ona point that moves a distance*d*in the direction of the forceis the product,A = F*d

The law of conservationof energy:

T1 + A = T2

T - kinetic energy

T = mv^2/2

A = T2 - T1 = m/2 (v2^2- v1^2)

v1= 7.5 m/s, v2 = 3.2 m/s

d= A/F = m/(2F) (v2^2 - v1^2) =15/(2*10) * (7.5^2 - 3.2^2) = 34.5 m

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