Question #22106

A large chunk of ice with a mass of 15.0 kg falls from a roof 8.00 m above the ground.
(a) What is the kinetic energy of the ice as it reaches the ground?
(b) What is its speed as it reaches the ground?

Expert's answer

The energy conservation law:

U + T = const

T - kinetic energy

U - potential energy

T = m*v^2/2

U = m*g*h

a) T = m*g*h = 15*8*10 =1200 J

b) v = Sqrt[2T/m]=Sqrt[2*1200/15] = 4*Sqrt[10] m/s = 12.6 m/s

U + T = const

T - kinetic energy

U - potential energy

T = m*v^2/2

U = m*g*h

a) T = m*g*h = 15*8*10 =1200 J

b) v = Sqrt[2T/m]=Sqrt[2*1200/15] = 4*Sqrt[10] m/s = 12.6 m/s

## Comments

## Leave a comment