Question #22105

A 450 kg compressor slides down a loading ramp that is 7.0 m long. Initially at rest, the compressor’s speed at the bottom of the ramp is 1.1 m/s. What is the magnitude of the net force acting on the compressor?

Expert's answer

From energy conservation law: all potential energy goes tokinetic, except work of external net force.

We can formulate it next way: T=W-A, t- kinetic, W-potential, A - work.

A=F*S

W=mgh

T=mv^2/2

So,

mv^2/2=mgh-f*s

mgh-mv^2/2=f*s

(m/s)(gh-v^2/2)=F

(450/7)(10*7-1.1^2/2)=F=4.371kN

We can formulate it next way: T=W-A, t- kinetic, W-potential, A - work.

A=F*S

W=mgh

T=mv^2/2

So,

mv^2/2=mgh-f*s

mgh-mv^2/2=f*s

(m/s)(gh-v^2/2)=F

(450/7)(10*7-1.1^2/2)=F=4.371kN

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