Answer on Mechanics | Relativity Question for tiffany
F = μ·M·g + M·a,
where μ = 0.0610116774619834, M = 47.02 kg, g = 9.8 m/s², a = 19.49 m/s² and F is sought-for force. In fact, the friction force (μ·M·g component) is already given and amounts 28.2 N. Therefore,
F = 28.2[N] + 47.02[kg]·19.49[m/s²] = 944.6198[N].
So, the force needed is
F = 944.6198[N].
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