# Answer to Question #21991 in Mechanics | Relativity for Willim

Question #21991

A sled is moving at a constant speed down a surface inclined at 45.0° with the horizontal and travels 30 meters in 4 seconds. Calculate the vertical velocity of the sled at the end of 4 seconds

Expert's answer

As speed is constant, V = d / t.

The vertical velocity Vx = V * cosA = d * cosA / t.

As d = 30 m and t = 4 s, V = 30 / 4 = 7.5 m/s and A = 45.0°,getting:

Vx = 30 * 1 / (4 * sqrt(2)) = 7.5 / sqrt(2) =approx. 5.3033 m/s.

The vertical velocity Vx = V * cosA = d * cosA / t.

As d = 30 m and t = 4 s, V = 30 / 4 = 7.5 m/s and A = 45.0°,getting:

Vx = 30 * 1 / (4 * sqrt(2)) = 7.5 / sqrt(2) =approx. 5.3033 m/s.

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Assignment Expert21.06.13, 14:28<div>You're welcome. We are glad to be helpful.</div><div>If you really liked our service please press like-button beside answer field. Thank you!</div><div>

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Alejandra alvarez20.06.13, 21:39thank you so much :)

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