Question #21739

A student wearing frictionless in-line skates in a horizontal surface is pushed by a friend with a constant force of 45N. How far must the student be pushed, starting from rest her final kinetic energy is 352J?

Expert's answer

T=A=F*d

T - the kinetic energy

A - the work done by a constant force of magnitude F on a body that moves a distance d in the direction of the force is the product

d=T/F=325/45=7.22 m

T - the kinetic energy

A - the work done by a constant force of magnitude F on a body that moves a distance d in the direction of the force is the product

d=T/F=325/45=7.22 m

## Comments

## Leave a comment