Answer to Question #21473 in Mechanics | Relativity for faisl
The velocity of a particle moving along the x-axis varies in
time according to the expression vx(t) = (40 – 5 t2) m/s, where t is in
Find the average acceleration in the time interval t=0 to t=2.0s.
Determine the acceleration at t = 2.0 s.
Acceleration is the rate at which the velocity of a body changes with time: a = dv/dt a - acceleration v - velocity In our case: ax = dvx(t)/dt ax = d/dt (40 - 5 t2) = -10t the average acceleration in the time interval t=0 to t=2.0s: a_av = [ax(0) + ax(2)]/2 = (0-20)/2 = -10m/s^2 the acceleration at t = 2.0 s ax(2) = -10*2 = -20 m/s^2