# Answer to Question #21221 in Mechanics | Relativity for MOHAMED

Question #21221

The momentum of a particle is p. The kinetic energy of the particle is doubled.

The momentum is now squre root of 2 p.. kindly explain how to get this

The momentum is now squre root of 2 p.. kindly explain how to get this

Expert's answer

The momentum of a particle is p. The kineticenergy of the particle is doubled.

The momentum is now square root of 2p.. kindly explain how to get this

p=m*v

p - The momentum of a particle

m- mass of a particle

v- velocity

E=m*v^2/2

E - The kinetic energy

E=m*(p/m)^2/2=p^2/(2m)

p=sqrt(2E*m)

p1=sqrt(2E1*m)

p2=sqrt(2E2*m)

p2/p1=sqrt(E2/E1)

If E2/E1=2

p2=p1*sqrt(2)

The momentum is now square root of 2p.. kindly explain how to get this

p=m*v

p - The momentum of a particle

m- mass of a particle

v- velocity

E=m*v^2/2

E - The kinetic energy

E=m*(p/m)^2/2=p^2/(2m)

p=sqrt(2E*m)

p1=sqrt(2E1*m)

p2=sqrt(2E2*m)

p2/p1=sqrt(E2/E1)

If E2/E1=2

p2=p1*sqrt(2)

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