68 326
Assignments Done
98,8%
Successfully Done
In November 2018

Answer to Question #20621 in Mechanics | Relativity for Bobby

Question #20621
A 34kg crate is is pushed with a horizontal force of 70N at a steady pace. Determine the value of the kinetic friction and the coefficient of kinetic friction.
Expert's answer
As the crate is moving at a steady pace, it's acceleration has zero value and according to the second Newton's law we can conclude that the friction force has the same value as the pushing force and is directed oppositely. So,

F(friction) = 70[N].

Let's find the coefficient of kinetic friction μ. We know that

F(friction) = μ·F(normal),

therefore

μ = F(friction)/F(normal) = 70[N]/(34[kg]*9.8[m/s²]) ≈ 0.21.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions