Answer to Question #205671 in Mechanics | Relativity for dara

Question

A heavy block is suspended from a vertical spring.

The elastic potential energy is stored in the spring is 4 J.

What is the spring constant if the elongation of the spring is 10 cm?

Answer 1

$\Delta l =10cm=0.1m$

$E_p=4\ J$

$E_p=\frac{k\Delta l^2}{2}$

$k= \frac{2E_p}{\Delta l^2}=\frac{2*4}{0.1^2}=0.08\ \frac{N}{m}$

$\text{Answer: }k=0.08\ \frac{N}{m}$