Question #20547

Force acting on a particle moving in a straight line varies with the velocity of the particle as F=k/v,where K is a constant.The work done by this force in time t is:

(A)K/v^2.t

(B)2Kt

(C)Kt

(D)2Kt/v^2

(A)K/v^2.t

(B)2Kt

(C)Kt

(D)2Kt/v^2

Expert's answer

The work is equal to the integral of force multiplied by velocity over time

hence A=int(K/v * v dt) = int(K dt) = Kt

answer is (C)Kt

hence A=int(K/v * v dt) = int(K dt) = Kt

answer is (C)Kt

Learn more about our help with Assignments: MechanicsRelativity

## Comments

## Leave a comment