Train breaks are applied it has covered covered 800 m distance reducing speed from 96km/h to 48km/h before going going to rest how much distance it covered.
From the statement we can get acceleration in time of reducing speed: v0-at2=v1 v1=at1 at1=48 at2=48 acceleration is constant, therefore: t1=t2 So, S1=v0t1-at1^2/2 S2=v1t1-at1^2/2 S2=S1-(v0-v1)t1 Now, we have to find t1 t1=48/a S=v048/a-a48^2/a^2/2 S/48^2=1.5/a So, 800/1.5*48^2=a a=4.32 t1=48/4.32 S2=800-48*48/4.32=266.(6) m
You may be familiar with the poignant phrase, “Work smarter, not harder.” Now, this could mean plenty of different things,…
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