# Answer on Mechanics | Relativity Question for zk

Question #20277

Q: A body weighing 2 kg tied at the end of string 1 meter long and rotating in a vertical circular path at a speed of 6 meter per second. What is the tension at the string at top and at bottom?

Expert's answer

**T**= m

**g**+ m

**a**

**T -**the tension at the string

**a**- the acceleration of the body

a = v^2/r

On the top:

T = ma - mg = m(v^2/r - g) = 2*(6^2/1-10) = 52 H

On the bottom:

T = ma + mg = m(a + g) = 2*(36+10) = 92 H

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## Comments

Assignment Expert28.12.2012 05:46You're welcome. We are glad to be helpful.

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gk28.12.2012 04:58Thanks for the solution. Cleared.

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