# Answer to Question #19422 in Mechanics | Relativity for Celesta

Question #19422

Calculate the moment of inertia I of the following system of two masses connected by a light rod of length 4 meters rotating about an axis O, 1 meter from mass 3kg and 3 meters from mass 5 kg.

Expert's answer

I = m1*r1^2 + m2*r2^2 = (3kg)*(1 m)^2 + (5 kg)*(3 m)^2 = 48 kg*m^2.

The moment of inertia of the rod is not accounted for, as we're assuming its

mass to be zero.

The moment of inertia of the rod is not accounted for, as we're assuming its

mass to be zero.

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