An object is placed 4 cm in front of a concave lens of focal length 3 cm. Using the lens equation, find where the image will form and state whether it is a real or virtual image.
1
Expert's answer
2012-11-29T08:56:27-0500
1/s2 = 1/f - 1/s1 we take negative focal length, because it is divergring lens 1/s2 = - 1/3 - 1/4 = - 7/12
s2 = 12/7 cm from the length, on the same side where object is. The image is virtual
Comments
Leave a comment