# Answer on Mechanics | Relativity Question for Joshua

Question #19386

How much heat must a refrigerator remove from 100 g of water at 25 º C to convert it to ice at 0º C? (Specific heat of water = 1 cal /gº C and heat of fusion of ice = 80 cal/g at 0º C)

Expert's answer

for cooling down to 0º C refrigerator must remove

100g* (1 cal /gº C) * 25 º C = 2500 cal

for converting into ice refrigerator must remove

100g* 80 cal/g = 8000 cal

Totally 2500+8000 = 10500 cal must be removed

100g* (1 cal /gº C) * 25 º C = 2500 cal

for converting into ice refrigerator must remove

100g* 80 cal/g = 8000 cal

Totally 2500+8000 = 10500 cal must be removed

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment