Question #19383

A cubical object of sides 5 cm is immersed completely in water. What is the force of buoyancy on the object? (Assume g = 10 m/s2)

Expert's answer

Force of buoyance is F=ro*g*V

r0=1000

g=10

V=5*5*5=25*5=125*10^-6

So, F=1250000*10^-6 N=1.25N

r0=1000

g=10

V=5*5*5=25*5=125*10^-6

So, F=1250000*10^-6 N=1.25N

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