# Answer on Mechanics | Relativity Question for ken

Question #1845

A proton is moving at 425 m/s. (a) How much work must be done on it to stop it?(answer in joules) (A proton has a mass of 1.67×10−27 kg.) (b) Assume the net braking force acting on it has magnitude 8.01×10−16 N and is directed opposite to its initial velocity. Over what distance must the force be applied?(in meters) Watch your negative signs in this problem.

Expert's answer

(a) While moving with a speed of 425 m/s proton has the following kinetic energy:

K = mv

Required work is equal to this energy.

(b) S = A/F = 1.51×10

K = mv

^{2}/2 = 1.67×10^{−27}* 425^{2}/2 = 1.51×10^{−22}JRequired work is equal to this energy.

(b) S = A/F = 1.51×10

^{−22}/ 8.01×10^{−16}N = 0.189×10^{−6}m.Need a fast expert's response?

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