Answer to Question #18309 in Mechanics | Relativity for Mary
A spring stretches by a 100 n force. The displacement of the end of the spring increases 5.0 cm beyond its original stretches positions when the force increases 20% to 120 n. calculate the force constant of the spring and its original displacement.
the difference in forces is proportional to difference ofdisplacement F_2 - F_1 = k x_2 - k x_1 = k (x_2-x_1) Hence 120-100 = k * 5cm 20 N = k* 5 cm k = 4 N/cm
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