Answer to Question #17380 in Mechanics | Relativity for uzair zaidi
An indestructible bullet 2.00 cm long is fired straight
through a board that is 10.0 cm thick. The bullet strikes
the board with a speed of 420 m/s and emerges with a
speed of 280 m/s. (a) What is the average acceleration
of the bullet as it passes through the board? (b) What is
the total time that the bullet is in contact with the
board? (c) What thickness of board (calculated to
0.1 cm) would it take to stop the bullet, assuming
the bullet’s acceleration through all parts of the board
is the same?
Total length in collision is 14sm S=at^2/2+v0t v1=v0-at a=(v0-v1)/t S=-(v0-v1)t/2+v0t=(v0+v1)t/2 0.14=350t a=140/t t=0.0004 a=3500 m/s So, for full stop: at=v0 t=v0/a S=at^2/2+v0t S=v0^2/2a+v0^2/a S=3v0^2/2a S=75.6 sm
It’s the most wonderful time of the year: Winter Holidays! Thanksgiving dinner was served, Black Friday has finished, and now…
APPROVED BY CLIENTS
I have used assignment experts multiple times and they have always been very timely. They submit work before the final deadline and always keep attentive and effective communication whenever I have needed help. Also, I think they have great prices and the work is superb!!! Thank you experts!!