Question #17136

a person in a kayak starts paddling, and it accelerates from 0 to .60 m/s in a distance of .41 m. If the combined mass if the person and the kayak is 73 kg, what is the magnitude of the net force acting on the kayak?

Expert's answer

Let's find the acceleration of a kayak:

V = at ==> t = V/a

D = at²/2 = a(V/a)²/2 = aV²/(2a²) = V²/(2a) ==> a = 2V²/D = 2*(0.60[m/s])²/0.41[m] = 1.76[m/s²].

According to the second Newton's law, the magnitude of the net force acting on the kayak is

F = m*a = 73[kg] * 1.76[m/s²] = 128.48[N]

V = at ==> t = V/a

D = at²/2 = a(V/a)²/2 = aV²/(2a²) = V²/(2a) ==> a = 2V²/D = 2*(0.60[m/s])²/0.41[m] = 1.76[m/s²].

According to the second Newton's law, the magnitude of the net force acting on the kayak is

F = m*a = 73[kg] * 1.76[m/s²] = 128.48[N]

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