# Answer to Question #17012 in Mechanics | Relativity for trey

Question #17012

A 11.8 N force acts horizontally on a 3.9 kg box sitting on a frictionless surface of ice. Determine the acceleration of the box.

Expert's answer

According to the second Newton's law the acceleration of the box is

a = F/m = 11.8[N] / 3.9[kg] ≈ 3.03 [m/s²].

a = F/m = 11.8[N] / 3.9[kg] ≈ 3.03 [m/s²].

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