Answer to Question #1684 in Mechanics | Relativity for dee

Question

The velocity of an 11-kg box changes from 5.1 m/s to 15 m/s. How much total work is done on the box?

Answer 1

The work would be equal to change of kinetic energy of the object:
A = mv₂²/2 - mv₁²/2 = m/2 (v₂²-v₁²) = 11/2 (15²-5.1²) = 1094.445 J.