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Answer to Question #1684 in Mechanics | Relativity for dee

Question #1684
The velocity of an 11-kg box changes from 5.1 m/s to 15 m/s. How much total work is done on the box?
Expert's answer
The work would be equal to change of kinetic energy of the object:
A = mv22/2 - mv12/2 = m/2 (v22-v12) = 11/2 (152-5.12) = 1094.445 J.

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