Answer to Question #1666 in Mechanics | Relativity for cory s
T1/T2 = 2 π(√ (L/g1)) / 2π (√(L/g2) = √(g2/g1)
As g = GM/R2, g1 = GM/R2, g2 = GM/(R+h)2, where h is the height of building, R the Earth's radius (6.38x106 m).
T1/T2 = √(g2/g1) = √((GM/(R+h)2) / (GM/R2)) = √(R2/(R+h)2) = R2/(R+h)2.
T1 = 60 min,
60/T2 = (6.38/(6.38+3.19))2
Answer: T2 = 135 min.
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