60 373
Assignments Done
98,1%
Successfully Done
In April 2018

Answer to Question #1666 in Mechanics | Relativity for cory s

Question #1666
It is the year 2305 and the tallest structure in the world has an insane height of 3.19×106 m above the surface of the Earth. A pendulum clock that keeps perfect time on the surface of the Earth is placed at the top of the tower. How long does the clock take to register one elapsed hour? The radius of the Earth is 6.38×106 m and its mass is 5.97×1024 kg. Answer in minutes.
Expert's answer
The periods on the ground and on the top of building are related by the expression:
T1/T2 = 2 π(√ (L/g1)) / 2π (√(L/g2) = √(g2/g1)

As g = GM/R2, g1 = GM/R2, g2 = GM/(R+h)2, where h is the height of building, R the Earth's radius (6.38x106 m).
T1/T2 = √(g2/g1) = √((GM/(R+h)2) / (GM/R2)) = √(R2/(R+h)2) = R2/(R+h)2.

T1 = 60 min,
60/T2 = (6.38/(6.38+3.19))2

Answer: T2 = 135 min.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions