# Answer to Question #16327 in Mechanics | Relativity for Zackery Holguin

Question #16327

A 34.0 crate is initially moving with a velocity that has magnitude 4.47 in a direction 37.0 west of north. much work must be done on the crate to change its velocity to 7.24 in a direction 63.0 south of east?

Expert's answer

Px1=m4.47*cos37=-3.57m

Py1=m4.47*sin37=2.64m

Px2=m7.24*cos63=3.29m

Py2=m7.24*sin63=-6.45m

deltaPx=m6.86

deltaPy=m9.09

DeltaP=m11.39

So, we had to change impulse on 11.39m=387.26.

For this we need force F=p^2/2m

So, F=2.25 kN

Work is A=F*S, so 2250S.

Py1=m4.47*sin37=2.64m

Px2=m7.24*cos63=3.29m

Py2=m7.24*sin63=-6.45m

deltaPx=m6.86

deltaPy=m9.09

DeltaP=m11.39

So, we had to change impulse on 11.39m=387.26.

For this we need force F=p^2/2m

So, F=2.25 kN

Work is A=F*S, so 2250S.

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