Question #16154

A 22 kg child is on a slide in a playground. She climbs 4.50 m to the top. Determine the velocity that the child would leave the slide if it was frictionless.

Expert's answer

When the child is at the top of the slide, its potential energy is

P = 22[kg]*9.8[m/s²]*4.5[m] = 970.2 J.

When the child slides down, its potential energy turns into kinetic energy:

P = K = 22[kg]*(V[m/s])²/2 = 970.2 J.

Therefore,

V = √(970.2*2/22)[m/s] ≈ 9.39 [m/s].

So, the velocity of a child will be about 9.39 [m/s].

P = 22[kg]*9.8[m/s²]*4.5[m] = 970.2 J.

When the child slides down, its potential energy turns into kinetic energy:

P = K = 22[kg]*(V[m/s])²/2 = 970.2 J.

Therefore,

V = √(970.2*2/22)[m/s] ≈ 9.39 [m/s].

So, the velocity of a child will be about 9.39 [m/s].

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