# Answer to Question #16125 in Mechanics | Relativity for Stephanie

Question #16125

Emily takes a trip, driving with a constant velocity of 81.5 km/h to the north except for a 22 min rest stop. If Emily's average velocity is 72.8 km/h to the north, how long does the trip take?

Expert's answer

Let's denote the driving time by T. Then the travelled distance can be expressed in a such way:

D = 72.8[km/h]*(T[h]+22[m]) = 72.8[km/h]*(T[h]+11/30[h]).

From the other side,

D = 81.5[km/h]*T.

So,

72.8[km/h]*(T[h]+11/30[h]) = 81.5[km/h]*T ==>

72.8*T + 72.8*11/30 = 81.5*T ==>

800.8/30 = 8.7*T ==>

T ≈ 3.09[h].

So, the trip took about (3.09 + 11/30) ≈ 3.46 hours.

D = 72.8[km/h]*(T[h]+22[m]) = 72.8[km/h]*(T[h]+11/30[h]).

From the other side,

D = 81.5[km/h]*T.

So,

72.8[km/h]*(T[h]+11/30[h]) = 81.5[km/h]*T ==>

72.8*T + 72.8*11/30 = 81.5*T ==>

800.8/30 = 8.7*T ==>

T ≈ 3.09[h].

So, the trip took about (3.09 + 11/30) ≈ 3.46 hours.

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