Answer to Question #15873 in Mechanics | Relativity for Dp
V = -3[m/s] + 2.75[m/s²]*5.00[s] = 10.75[m/s].
T = 3[m/s]/2.75[m/s²] = 12/11 seconds
the man will stop. After that he begin to run in the positive direction. So, his displacement is
D = 2.75[m/s²]*(5.00[s]-12/11[s])²/2 ≈ 21 metres
in positive direction.
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