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Answer to Question #15823 in Mechanics | Relativity for Lexie
Question #15823
An object (moving man) starts from rest and accelerates at a rate of 4.3 m/s^2 for 2.05 seconds. What is his displacement from the start position?
Expert's answer
We can find the displacement of a man by the next formula:
D = at²/2 = 4.3[m/s²]*2.05[s]²/2 = 4.4075[m].
D = at²/2 = 4.3[m/s²]*2.05[s]²/2 = 4.4075[m].
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