Answer to Question #15713 in Mechanics | Relativity for Belmin Boracic
A worker drops a wrench from the top of a tower 96 m tall. What is the velocity of the wrench when it strikes the ground?
Let's find the time of falling. We know that
H = gT²/2,
T = √(2H/g)
and therefore we can find velocity:
V = gT = g√(2H/g) = 9.8[m/s²]√(2*96[m]/9.8[m/s²]) ≈ 43.38[m/s].
So, the wrench strikes the ground with velocity of about 43.38m/s.