# Answer to Question #15713 in Mechanics | Relativity for Belmin Boracic

Question #15713

A worker drops a wrench from the top of a tower 96 m tall. What is the velocity of the wrench when it strikes the ground?

Expert's answer

Let's find the time of falling. We know that

H = gT²/2,

so

T = √(2H/g)

and therefore we can find velocity:

V = gT = g√(2H/g) = 9.8[m/s²]√(2*96[m]/9.8[m/s²]) ≈ 43.38[m/s].

So, the wrench strikes the ground with velocity of about 43.38m/s.

H = gT²/2,

so

T = √(2H/g)

and therefore we can find velocity:

V = gT = g√(2H/g) = 9.8[m/s²]√(2*96[m]/9.8[m/s²]) ≈ 43.38[m/s].

So, the wrench strikes the ground with velocity of about 43.38m/s.

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