Answer to Question #15697 in Mechanics | Relativity for gamal
5 sec later it is rolling down the hill at 6.0 m/s
what is the acceleration and displacement
a = (6.0[m/s] - 4.0[m/s])/5[s] = 0.4[m/s²].
So, the displacement is
D = 4.0[m/s]*5[s] + 0.4[m/s²]*(5[s])²/2 = 25 meters.
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