Question #15662

a man walks across a linoleum floor. he was a weight of 250 pounds, and the soles of his shoes have a surface area of 37.20 in^2. what force in newtons and pressure in pascals will he exert on the floor as he walks across the floor?

Expert's answer

According to the second Newton's law the force exerted on the floor is

F = Mg = 250[p]*9.8[m/s²] = 113.4[kg]*9.8[m/s²] = 1111.3[N].

The pressure is

P = 1111.3[N]/37.20[in²] = 1111.3[N]/240.0[cm²] = 4.6[P].

F = Mg = 250[p]*9.8[m/s²] = 113.4[kg]*9.8[m/s²] = 1111.3[N].

The pressure is

P = 1111.3[N]/37.20[in²] = 1111.3[N]/240.0[cm²] = 4.6[P].

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