65 671
Assignments Done
99,2%
Successfully Done
In October 2018

Answer to Question #15643 in Mechanics | Relativity for anushka

Question #15643
a boy sitting on a swing at a maximum height of 5m above the ground.when the swing passes through the mean position which is 2m above the ground its velocity is?
Expert's answer
The law of conservation of energy states that the total amount of
energy in
an isolated system remains constant over time.
At a maximum height:
K0 =
0
P0 = m * g * H
At a lowest point:
K1 = m * V^2 / 2
P1 = m * g *
h

K0 + P0 = K1 + P1, so:
m * g * H = m * V^2 / 2 + m * g * h
g * H
= V^2 / 2 + g * h
V^2 / 2 = g * H - g * h
V = sqrt(2 * g * (H - h))
V =
sqrt(2 * 9.81 * (5 - 2)) = 7.67 m/s

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions