Answer to Question #15613 in Mechanics | Relativity for Melissa
V = S*sin(42°).& (1)
The vertical component of the ball's velocity turns to zero at the highest point of the flight. Also, the highest point of the flight is reached at the half of the flight time. So,
V = gT/2 = 9.8[m/s²]*2.20[s]/2 = 10.78 m/s.
As follows from (1),
I = V/sin(42°) = 10.78[m/s]/sin(42°) ≈ 16.11 m/s.
So, the initial velocity of the ball was about 16.11 m/s.
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