Answer to Question #15558 in Mechanics | Relativity for laura
A. 15yd, east B.15 yd, west C. 15yd
D.50yd, east E. 50yd, west F. 50yd
G. 60yd, east H. 60yd west I. 60yd
J. 85yd east K. 85yd west L. 85yd
M. 145 yd east N. 145yd west O. 145yd
or P. none of these
So, the first part of his displacement is
D1 = 40 - 10 = 30 yards.
2. He turns around and walks to the 0 yard line.
Coach starts from the 40-yard line and walks to the 0 yard line, so his displacement is
D2 = 40 - 0 = 40 yards.
3. He turns once more and walks back to the 50 yard line.
Coach starts from the 0-yard line and walks to the 50-yard line, so his displacement is
D3 = 50 - 0 = 50 yards.
4. He turns around once more and walks back to the 25 yard line.
Coach starts from the 50-yard line and walks to the 25-yard line, so his displacement is
D4 = 50 - 25 = 25 yards.
The total distance walked is
D = D1 + D2 + D3 + D4 = 30 + 40 + 50 + 25 = 145 yards.
So, correct answer is O.
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