# Answer to Question #15493 in Mechanics | Relativity for Angel

Question #15493

While exploring a cave, a spelunker starts at the entrance and moves the following distances: 75.0m north, 300m east, 210m at angle of 30.0 degrees north of east, and 150m south. Find the resultant displacement from the cave entrance.

Expert's answer

Assuming north and east directions as positive, getting:

N = 75.0 + 210 *

sin30 - 150 = 30 m

E = 300.0 + 210 * cos30 = 481.9 m

So, the resultant

displacement L = sqrt( N^2 + E^2 ) = sqrt(900 +232194) = 482.8 m

N = 75.0 + 210 *

sin30 - 150 = 30 m

E = 300.0 + 210 * cos30 = 481.9 m

So, the resultant

displacement L = sqrt( N^2 + E^2 ) = sqrt(900 +232194) = 482.8 m

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